[OMPI users] fortran program with integer kind=8 using openmpi‏

[William Au]

Dear all,

Thank you for all responses. There is another problem using  
-fdefault-integer-8.
I am using 1.6..

For the i8:
configure:44650: checking for the value of MPI_STATUS_SIZE
configure:44674: result: 3 Fortran INTEGERs
configure:44866: checking if Fortran compiler works
configure:44895: /usr/bin/gfortran44 -o conftest -m64  -g -fPIC 
-fdefault-integer-8  -fexceptions  conftest.f  >&5
configure:44895: $? = 0

MPI_STATUS_SIZE 3

For the i4:
configure:44650: checking for the value of MPI_STATUS_SIZE
configure:44674: result: 6 Fortran INTEGERs
configure:44866: checking if Fortran compiler works
configure:44895: gfortran -o conftest -m64 -g -fPIC  -fexceptions  conftest.f  
>&5

MPI_STATUS_SIZE 6


For i8,  I found out later in   pstatus_c2f.c

for( i = 0; i < (int)(sizeof(MPI_Status) / sizeof(int)); i++ )
        f_status[i] = OMPI_INT_2_FINT(c_ints[i]);

It will try to write 6 integers to f_status and hence out of array bound.

We need to change the configure to set MPI_STATUS_SIZE right in this case.

Thanks.

Regards,

William