On May 7, 2012, at 8:31 PM, Jingcha Joba wrote: > So in the above stated example, end-start will be: <whatever the solver took> > + 20ms ? > > (time slice of P2 + P3 = 20ms)
More or less (there's nonzero amount of time required for the kernel scheduler, and the time quantum for each of P2 and P3 is likely not *exactly* 10ms). But you're over thinking this. The elapsed wall-clock time is simply (end-start). -- Jeff Squyres jsquy...@cisco.com For corporate legal information go to: http://www.cisco.com/web/about/doing_business/legal/cri/
