On Tue, Jul 27, 2010 at 08:11:39AM -0400, Jeff Squyres wrote: > On Jul 26, 2010, at 11:06 PM, Hugo Gagnon wrote: > > > 8 integer, parameter :: dp = kind(1.d0) > > 9 real(kind=dp) :: inside(5), outside(5) > > I'm not a fortran expert -- is kind(1.d0) really double precision? According > to http://gcc.gnu.org/onlinedocs/gcc-3.4.6/g77/Kind-Notation.html, kind(2) is > double precision (but that's for a different compiler, and I don't quite grok > the ".d0" notation).
*quote* kind (x) has type default integer and value equal to the kind type parameter value of x. *end quote* p. 161 from Metcalf et al (2007) Fortran 95/2003 explained. % cat tmp.f90 program z integer, parameter :: dp = kind(1.d0) real(kind=dp) :: inside(5), outside(5) write(*,*)dp end program z % g95 -L/usr/local/lib tmp.f90 % ./a.out 8 % Kind 8 is (on most arch) 8-byte real, i.e. typically double precision. -- Anton Shterenlikht Room 2.6, Queen's Building Mech Eng Dept Bristol University University Walk, Bristol BS8 1TR, UK Tel: +44 (0)117 331 5944 Fax: +44 (0)117 929 4423