While using the BLACS test programs, I've seen that with recent SVN checkouts
(including todays) the MPI_Abort test left procs running. The last SVN I
have where it worked was 1.4a1r20936. By 1.4a1r21246 it fails.

Works O.K. in the standard 1.3.2 release.

A test program is below. GCC was used.

DM

#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
#include <math.h>
#include <mpi.h>

#define NUM_ITERS 100000

/* Prototype the function that we'll use below. */

static double f(double);

int
main(int argc, char *argv[])
{
  int iter, rank, size, i;
  int foo;
  double PI25DT = 3.141592653589793238462643;
  double mypi, pi, h, sum, x;
  double startwtime = 0.0, endwtime;
  int namelen;
  char processor_name[MPI_MAX_PROCESSOR_NAME];

  /* Normal MPI startup */

  MPI_Init(&argc, &argv);
  MPI_Comm_size(MPI_COMM_WORLD, &size);
  MPI_Comm_rank(MPI_COMM_WORLD, &rank);
  MPI_Get_processor_name(processor_name, &namelen);

  printf("Process %d of %d on %s\n", rank, size, processor_name);

  /* Do approximations for 1 to 100 points */

  /* sleep(5); */
  for (iter = 2; iter < NUM_ITERS; ++iter) {
    h = 1.0 / (double) iter;
    sum = 0.0;

    /* A slightly better approach starts from large i and works back */

    if (rank == 0)
      startwtime = MPI_Wtime();

    for (i = rank + 1; i <= iter; i += size) {
      x = h * ((double) i - 0.5);
      sum += f(x);
    }
    mypi = h * sum;

    if(iter == (NUM_ITERS - 1000)){
     MPI_Barrier(MPI_COMM_WORLD);
     if(rank == 2){
      MPI_Abort(MPI_COMM_WORLD, -1);
     } else {
      /* Just loop */
      foo = 1;
      while(foo == 1){
       foo = foo + 3;
       foo = foo - 2;
       foo = foo - 1;
      }
     }
    }
    MPI_Reduce(&mypi, &pi, 1, MPI_DOUBLE, MPI_SUM, 0, MPI_COMM_WORLD);
  }

  /* All done */

  if (rank == 0) {
   printf("%d points: pi is approximately %.16f, error = %.16f\n",
           iter, pi, fabs(pi - PI25DT));
   endwtime = MPI_Wtime();
   printf("wall clock time = %f\n", endwtime - startwtime);
   fflush(stdout);
  }

  MPI_Finalize();
  return 0;
}

static double
f(double a)
{
  return (4.0 / (1.0 + a * a));
}



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