08/16/2014 04:14 PM, Mark C. Allman wrote:
On Sun, 2014-08-17 at 00:42 +0200, Suvayu Ali wrote:
On Sat, Aug 16, 2014 at 02:44:14PM -0700, Mike Wright wrote:
Hi all,
I'm trying to write a simple script that if provided an argument, uses that,
or if nothing is provided, uses a predefined string.
if [ -n $# ]
This will always be true. -n tests if a string is empty or not. 0
counts as non-empty. You should use one of the comparison operators.
Try something like this:
[ $# -gt 0 ]
Hope this helps,
--
Suvayu
Open source is the future. It sets us free.
Are you looking for behavior that the following test script
demonstrates?
#!/bin/bash
theArg=${1:-The Default Value}
echo $theArg
Thanx Mark,
Very elegant. I like it.
I was just going through the section on "variable substitution" in "Unix
in a Nutshell" and saw that.
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