On Mon, 19 Aug 2013, Mark Haney wrote:
I've hit a problem I can't quite figure out which a bash script I'm writing. I'm trying to copy backup files in the format 2013-August-18--1123.zip to an NFS share. I want to have the script copy the file with just the date. In bash I've setup vars that get the current date: # Date variables log_year=`date "+%Y"` log_month=`date "+%B"` log_day=`date "+%d"`# Filename format YYYY_MM_DD--HHMM.zip filename=$log_year"-"$log_month"-"$log_day"--"/*".zip" The problem is I don't really care about the stuff after the '--'. I.e. from the CLI I'd just 'ls 2013-August-18--*.zip' to get all the files with that date in the file name. How can I do that in a bash script? -- Caesar si viveret, ad remum dareris. Mark Haney Software Developer/Consultant mark.ha...@gmail.com
You mean something like this? ************************ #!/bin/sh # Date variables log_year=`date "+%Y"` log_month=`date "+%B"` log_day=`date "+%d"` # Filename format YYYY_MM_DD--HHMM.zip filename="$log_year-$log_month-$log_day--*.zip" filelist=`ls $filename` echo $filelist *************************** billo
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