[updated, keeping original post and adding new info at bottom]
On 5/22/2012 8:12 PM, Paul Allen Newell wrote:
Hello:
As I continue dealing with iptables, another issue has come up that I
can't tell is a mis-understanding on my part or a potential problem
I have three F16 machines, one x86_64 and two i383/686. If I run
/sbin/ifconfig on them, I get (short summary of):
x86_64: eth0
i686: em1
Looking in /etc/sysconfig/network-scripts, I can see only ifcfg-em1
and no ifcfg-eth0 on all the machines (x86_64 and i686).
The closest bugzilla I can see if 784314 but it looks like it hints
that ifconfig is old-school and the right way to do things (and its
F17 not F16).
Does anyone know what I am either doing wrong or if this looks like a
problem/bug. Plus, if there is a better way, I'd love to know.
What I want to do is have is a bash way to get the static ip address
of the machine which I can see in eth0/em1. I've been using something
I found online which assumes everything is eth0 (as in I think it was
for older Fedora):
+++
/sbin/ifconfig eth0 | grep 'inet addr:' | cut -d: -f2 | awk '{ print $1}'
+++
Its too clever for me to have come up with on my own (smile).
I tried expanding the grep to be 'inet addr:192.168.2' but that failed
on the laptop which has an entry for wireless which is dhcp (I cannot
assume wireless will be 192.168.2.*).
Any suggestions appreciated,
Thanks,
Paul
Okay, so I managed to figure out that 'ip' is the new command. I'd
looked at it earlier to try to find a way around this, but couldn't
figure it out. Just spotted the 'obsolete, use ip' in man page of
ifconfig. As usual, there is always something discovered right after I
make the post.
Should I assume that even if ifconfig is giving a problem, its academic
and I should just focus on ip. And, if so, how the heck does one get the
ip addr. If I use "ip addr show", I still get eth0 on the x86_64 and em1
on the i686?
Thanks,
Paul
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