.
       After changing /etc/default/grub [as part of my attempt to make
       a nice clean text boot display] to look as below:

       [root@box6 bobg]# cat /etc/default/grub
       GRUB_TIMEOUT=15
       GRUB_DISTRIBUTOR="Fedora"
       GRUB_DEFAULT=saved
       GRUB_CMDLINE_LINUX="rd.md=0 rd.lvm=0 rd.dm=0  KEYTABLE=us
       SYSFONT=latarcyrheb-sun16 rd.luks=0 LANG=en_US.UTF-8"

       I did the following as was suggested:

       [root@box6 bobg]# grub2-mkconfig  -o  /boot/grub2/grub.cfg

       Generating grub.cfg ...
       Found linux image: /boot/vmlinuz-3.1.7-1.fc16.x86_64
       Found initrd image: /boot/initramfs-3.1.7-1.fc16.x86_64.img
       Found linux image: /boot/vmlinuz-3.1.0-7.fc16.x86_64
       Found initrd image: /boot/initramfs-3.1.0-7.fc16.x86_64.img
          No volume groups found
       done

       And everything works pretty much the way I would like it to
       except that now I have to select the kernel version to boot else
       it boots to the older one.

       The grub screen shows them listed in the following order and
       defaults to  the third line 3.1.0-7.fc16.x86_64 which I believe
       is not what it should do?

           3.1.7-1.fc16.x86_64
           3.1.7-1.fc16.x86_64 Recovery Mode
           3.1.0-7.fc16.x86_64
           3.1.0-7.fc16.x86_64 Recovery Mode

       Assuming that 3.1.7-1.fc16.x86_64 is the later version how do I
       fix that?

       The old grub was a lot less mysterious and easier to deal with.

       Bob





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