On 03/07/2011 04:08 PM, Sergio Belkin wrote: > Hi, > I am writing a script that it searchs for a file. I'd want to exit > with status non-zero if the file is not found. But find cannot do > that. > find command only exit with status non-zero one file is not processed > successfully. > > locate command con do that, but it cannot find a file from a given directory. > > How can I do it? > > Thanks in advance!
I find that if I'm in a directory and do a "find <filename>" and it fails the exit code is 1 (re: $? = 1). So if I'm in a directory that has files a b c and d and do "find a" I get an exit code of 0 (success) but if I do a "find e" I get exit code of 1 (failure) along with a failure message. So in your script you could do: #!/bin/bash cd <somedir> find <filename> 2> /dev/null if [ "$?" != "0" ] then exit 1 fi Strangely enough, if I'm in a directory and do a "find . -name e" (where e doesn't exist) I get *no* failed message and an exit code of 0. I find that a bit odd as I would think that "find e" and "find . -name e" would be the same thing. Perhaps that's something to do with the bash shell? kevin -- users mailing list users@lists.fedoraproject.org To unsubscribe or change subscription options: https://admin.fedoraproject.org/mailman/listinfo/users Guidelines: http://fedoraproject.org/wiki/Mailing_list_guidelines
