On Sun, 2011-01-02 at 14:27 -0800, S Mathias wrote:
> $ ASDF=hello; a=0; a=$(( 70 - $(echo $ASDF | awk '{print length}') )); echo
> "$a $ASDF"$(for i in {1..$a}; do printf "."; done)
> 65 hello.
> $
>
>
> Why doesn't it print:
> 65 hello.................................................................
>
>
>
> What am i missing?
The expression {1..$a} is being quoted and treated as a string, instead
of being evaluated. If you change the printf from:
printf "."
...to:
printf "[$i]"
...you'll see what's happening.
-Chris
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