Hi, thanks for reading my letter,
I got a problem , when I use apache2.24 ‘s proxy module to connect tomcat5.0.28
, I can’t get client IP Address by request.getRemoteAddr(),
I have also tried
request.getHeader("x-forwarded-for");
request.getHeader("Proxy-Client-IP");
request.getHeader("Proxy-Client-IP");
request.getHeader("WL-Proxy-Client-IP");
all of them doesn’t work , can you give me some adverise?
thank you !
doesn’t work, means
request.getHeader("x-forwarded-for") =null
,request.getHeader("Proxy-Client-IP")=null
request.getHeader("Proxy-Client-IP")=null,request.getHeader("WL-Proxy-Client-IP")=null,
so I can’t get client IP address
_____
发件人: Luis Moreira [mailto:[EMAIL PROTECTED]
发送时间: 2007年9月21日 17:29
收件人: users@httpd.apache.org
主题: Re: [EMAIL PROTECTED] NameVirtualHost question
What do you mean by "it doesnt work" ?
Have you checked your logs, to see (for instance) if Apache is fetching files
from the wrong root?
Luis
Matus UHLAR - fantomas wrote:
On 17.09.07 13:29, Néstor Boscán wrote:
I have a server that has an Apache Server 1.3. The server only has 1 IP and
can be access using two differente names server1 and server2. I would like
to create a VirtualHost for each name that sets the ServerName. Now I tried
the following
NameVirtualHost ip:80
<VirtualHost server1:80>
<VirtualHost server2:80>
NameVirtualHost and VirtualHost should have the same argument.
And it doesn't work. It will not use the VirtualHosts. I also tried this:
NameVirtualHost ip:80
<VirtualHost ip:80>
ServerName server1
<VirtualHost ip:80>
ServerName server2
And again it doesn't work.
this should work, unless there's configuration error elsewhere.
--
Luis Moreira
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