We tryied to have two different kinds of casts. The normal one, that is
more in the style of Java, which tries the cheapest way. And the "as"
version, which calls into asType is customizable and usually does more
expensive operations. The fallback for asType is the normal cast. That's
why we see asType as an extended cast. But don't expect asType simply as
something that allows for more cases than the normal cast. I can have
different conversion logic.
Now
new BigDecimal(d)
is much cheaper than
new BigDecimal(d.toString())
That those two do not match is actually because of d.toString(), which
does simply give 1.9 here, instead of the exact double value. That this
toString() methods behaves in this way has not always been the case afaik.
bye Jochen
Am 11.01.2016 um 10:57 schrieb Alberto Vilches:
Yes, I know the "1.9" literal in Groovy results in a BigDecimal. That's
why I'm trying to force the double using the "d", but maybe is still a
bigdecimal. So, let's try again:
Double d = 1.9
println((BigDecimal)d)
prints "1.899999999999999911182158029987476766109466552734375"
and
Double d = 1.9
println d as BigDecimal
prints "1.9"
On Fri, Jan 8, 2016 at 1:34 PM, Naresha K. <naresh...@gmail.com
<mailto:naresh...@gmail.com>> wrote:
Value 1.9 will be of type BigDecimal.
Why are you using D?
On Fri, Jan 8, 2016 at 5:45 PM, Alberto Vilches <vilc...@gmail.com
<mailto:vilc...@gmail.com>> wrote:
Hi everybody! We have an issue in our application, and we
realized these two lines have differents results. We wonder why
because we think it should calls to the
DefaultGroovyMethods.asType(Number self, Class<T> c). But it
seems only the explicit call to "as" finally calls to the asType
and the casting do a different thing (just a new
BigDecimal(1.9D), but we wonder in which part of Groovy is
happening)
(BigDecimal)1.9D //
"1.899999999999999911182158029987476766109466552734375" ->
1.9D as BigDecimal // "1.9"
In fact, we tried to put these two lines in the Groovy console
and see the AST in all the phases. But in all of them shows the
same code:
public java.lang.Object run() {
((1.9) as java.math.BigDecimal)
return ((1.9) as java.math.BigDecimal)
}
Somebody please could give some light? Thank you very much and
happy new year :)
--
Un saludo.
Alberto Vilches
--
Un saludo.
Alberto Vilches
