At 13:44 23/01/2013 +0100, Kolbjørn Stuestøl wrote:
Den 23.01.2013 07:29, skreiv Brian Barker:
At 22:57 22/01/2013 +0100, Kolbjørn Stuestøl wrote:
Is there any way to find the first occurrence
of a number less (or greater) than a given
number in an unsorted array or a column?
Example: A1:A31 contains a list of
temperatures a given month. I would like to
find the first day the temperature is below 0 degrees (metric).
What happens if there is no day in the month
when the temperature was negative? Let's say
you want the value zero for the resulting day number in this case.
This is a little messy, but it works:
o In B1, enter =A1<0 and fill it down the
column to B31. This generates TRUE for your
negative values and FALSE otherwise.
o In your result cell, enter
=N(MATCH(TRUE;B1:B31;0)) . The MATCH()
function searches for the first TRUE value in
the column B values and returns the relative
position in the array of the first
match. (Note that this is not necessarily the
row number, though will be in your
example.) This would return the #N/A error if
there is no negative temperature; the N()
function makes no change to real dates but converts this error to zero.
Alas the N() function does not works as
supposed. It returns "#N/A" if there are no
numbers below zero. I have to figure out a solution.
Oh dear: sorry. It indeed appears that the
behaviour of N() was changed (between versions
3.5. and 3.6) and it no longer works as I'd
imagined. So you'll need something (even messier) such as
=IF(ISERROR(MATCH(TRUE;B1:B31;0));0;MATCH(TRUE;B1:B31;0))
instead.
I trust this helps.
Brian Barker
--
For unsubscribe instructions e-mail to: [email protected]
Problems? http://www.libreoffice.org/get-help/mailing-lists/how-to-unsubscribe/
Posting guidelines + more: http://wiki.documentfoundation.org/Netiquette
List archive: http://listarchives.libreoffice.org/global/users/
All messages sent to this list will be publicly archived and cannot be deleted
