OK, sorry, I actually read the documentation on bindings and did use
{{MyProcessor}} as the bean name.
But it didn't work.
I register my bean/processor as:
registry.bind("MyProcessor", new MyProcessor(""));
But when I run it, I got:
Failed to resolve endpoint: bean://MyProcessor-1?method=process due to: No
bean could be found in the registry for: MyProcessor-1
Don't know where the "-1" comes from. However when I register it with that
registry.bind("MyProcessor-1", new MyProcessor(""));
Then the route works but not with the routetemplate parameter (because it's
already iniaitized. So I tried it with
registry.bind("MyProcessor-1", MyProcessor.class);
Caused by: org.apache.camel.ResolveEndpointFailedException: Failed to
resolve endpoint: bean://MyProcessor-1?method=process due to:
java.lang.NoSuchMethodException:
I also tried it with method parameters, instead of the constructor. I first
tried to put an extra parameter on the process method, but the interface
for Processor doesn't allow that. So I tried to use method overloading, but
then it's unclear how to pass the exchange object as a parameter.
Raymond
On Thu, Sep 8, 2022 at 12:06 PM Claus Ibsen <claus.ib...@gmail.com> wrote:
> Hi
>
> No you cannot - you mix standard Java with Camel "parsing" the model when
> it calls the configure() method.
> It would be the same in regular Camel route.
> You basically do standard Java code with a new constructor and pass in a
> string literal. Camel is not in use at that point.
>
> In your template bean example, then you need to use {{MyProcessor}} as the
> bean name.
> See the IMPORTANT note at:
>
> https://camel.apache.org/manual/route-template.html#_binding_beans_to_route_template
>
>
>
> On Thu, Sep 8, 2022 at 11:53 AM ski n <raymondmees...@gmail.com> wrote:
>
> > Hi,
> >
> > I have a routetemplate as follows:
> >
> > routeTemplate("processortemplate")
> > .templateParameter("out")
> > .from("direct:in")
> > .process("MyProcessor")
> > .to("{{out}}");
> >
> > This works.
> >
> > The processor is registered an the called by reference. Now I added a
> > constructor argument to the processor and I tried to call it like this:
> >
> > routeTemplate("processortemplate")
> > .templateParameter("processerParam")
> > .templateParameter("out")
> > .from("direct:in")
> > .process(new MyProcessor("{{processorParam}}"))
> > .to("{{out}}");
> >
> > This doesn't work, because the parameter of the processor is parsed
> before
> > the template parameter is parsed. Result is that the parameter
> > {{myProcessorParam}} is passed as literal param.
> >
> > I tried to come with up something like this:
> >
> > routeTemplate("processortemplate")
> > .templateParameter("processerparam")
> > .templateParameter("out")
> > .templateBean("MyProcessor")
> > .typeClass("com.foo.MyProcessor")
> > .property("processerparam", "{{processerparam}}")
> > .end()
> > .from("direct:in")
> > .to("bean:MyProcessor?method=process")
> > .to("{{out}}");
> >
> > But this didn't pass the parameter as well. As a workaround I set
> > constructor argument as a header and then get the header within the
> > processor.
> >
> > Question:
> >
> > Is there a way to pass constructor arguments to a processor in another
> way?
> > I couldn't find anything at the routeTemplate page on how to handle
> > processors.
> >
> > Raymond
> >
>
>
> --
> Claus Ibsen
> -----------------
> http://davsclaus.com @davsclaus
> Camel in Action 2: https://www.manning.com/ibsen2
>
