Hello,
is there a way on the on exception or in the error handler to send a message
one time and keep retrying?
Something like this but with error handler or on exception.
<route>
<from uri="activemq:in"/>
<doTry>
<throw new="sql.Exception"/>
<doCatch>
<exception>java.sql.SQLException</exception>
<choice>
<when>
<simple>${header.Reported} ==
null</simple>
<setHeader headerName="Reported">
<simple>true</simple>
</setHeader>
<multicast>
<to uri="activemq:NOTIFY"/>
<to uri="activemq:in"/>
</multicast>
</when>
<otherwise>
<to uri="activemq:in"/>
</otherwise>
</choice>
</doCatch>
</doTry>
</route>
Any suggestion will be appreciated.
Cecilio.
--
View this message in context:
http://camel.465427.n5.nabble.com/On-exception-notify-first-error-tp5767385.html
Sent from the Camel - Users mailing list archive at Nabble.com.