Please ignore this topic as the problem was due a typo in my jsp. I apologize for wasting your time on an issue that is not a problem, I should have checked more carefully.
regards, ----- Original Message ---- From: Struts Two <[EMAIL PROTECTED]> To: Struts Users Mailing List <user@struts.apache.org> Sent: Friday, October 31, 2008 5:43:55 PM Subject: Re: How to run an iterator twice in a page I was hoping to find a better way to do this for a case as simple as the this one rather than resorting to hacks. Normally in JSTL when c:foreach is used a new iterator is created. I also tried the following in the second iterator but of no avail <s:iterator value="[1].users" id="u" status="status"> I also tried to move users into request scope [ <s:set id="users" name="users" scope="request" value="users"/>] and then try <s:iterator value="#request.users" id="u" status="status"> in both iterators, But only the first table is displayed. ----- Original Message ---- From: "Peterson, Ryan" <[EMAIL PROTECTED]> To: Struts Users Mailing List user@struts.apache.org Sent: Friday, October 31, 2008 5:10:39 PM Subject: RE: How to run an iterator twice in a page It's sort of "hack-ish", but can you make a copy of the list of users in the Java code, and iterate over the copied list for the 2nd set of results? -----Original Message----- From: Struts Two [mailto:[EMAIL PROTECTED] Sent: Friday, October 31, 2008 1:36 PM To: Struts Users Mailing List Subject: How to run an iterator twice in a page I have a list of users and I would like to iterate over this list twice in a page. However in the following code snippet, The list is iterated only once and the second iterator displays nothing. <p>Table 1</p> <table cellspacing="1" cellpadding="0" class="basic-table" width="100%"> <tr class="gray-med-dark"> <th nowrap="nowrap" scope="col">user id</th> <th nowrap="nowrap" scope="col">user name</th> </tr> <s:iterator value="users" id="u" status="status"> <tr > <td><s:property value="#u.id" /></td> <td><s:property value="#u.name" /></td> </tr> </s:iterator> </table> <p>Table 2</p> <table cellspacing="1" cellpadding="0" class="basic-table" width="100%"> <tr class="gray-med-dark"> <th nowrap="nowrap" scope="col">user id</th> <th nowrap="nowrap" scope="col">user name</th> </tr> <s:iterator value="users" id="u" status="status"> <tr > <td><s:property value="#u.id" /></td> <td><s:property value="#u.name" /></td> </tr> </s:iterator> </table> In the second iterator I even renamed the id to u1 but of no avail. I think in the first iterator all the user objects are pushed on the top of stack hence users is not availabe on the second iterator. I would appreciate any hints on how to achieve this. __________________________________________________________________ Looking for the perfect gift? Give the gift of Flickr! http://www.flickr.com/gift/ --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] __________________________________________________________________ Be smarter than spam. See how smart SpamGuard is at giving junk email the boot with the All-new Yahoo! Mail. Click on Options in Mail and switch to New Mail today or register for free at http://mail.yahoo.ca --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] __________________________________________________________________ Ask a question on any topic and get answers from real people. Go to Yahoo! Answers and share what you know at http://ca.answers.yahoo.com --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
