First, is '/servlet' the name of your webapp? If so then this might just make sense. Why?
The HttpServletRequest.getServletPath() object is described to: > Returns the part of this request's URL that calls the servlet. In a filter, that is the mapping '/*' which as you wrote resulted in '/servlet'. Well, assuming '/servlet' is the name of your webapp and not your servlet. In a servlet, how did you do your web.xml mapping for the servlet which resulted in this result '/servlet/package.ServletName' ? Regards, David --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
