Because when you uncheck a checkbox you don't send this field and the
form process let the previous value in place
One of tips of mine is to put a hidden field with the same name and to
see the field as an array : when it contains only one value the
checkbox is unchecked, checked otherwise
Hope it will help,
Cedric
On Tue, 8 Feb 2005 13:58:22 -0800 (PST), Norris Shelton
<[EMAIL PROTECTED]> wrote:
> I have a checkbox drawn by:
> <html:checkbox property="recordTypebooking"
> onclick="javascript:${recordType.name}BoxDisplay();" />
> ${recordType.description} <br />
>
> The form is defined as:
> <form-bean name="searchNameForm"
> type="org.apache.struts.validator.LazyValidatorForm" >
> ...
> <!-- default recordTypeBooking to booking -->
> <form-property name="recordTypebooking"
> type="java.lang.Boolean" initial="true"/>
> ...
> </form-bean>
>
> The check box displays correct and even defaults. If I uncheck
> the box and submit, when it failes validation, it is still
> checked.
>
> =====
>
> Norris Shelton
> Software Engineer
> Sun Certified Java 1.1 Programmer
> Appriss, Inc.
> ICQ# 26487421
> AIM NorrisEShelton
> YIM norrisshelton
>
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