If not set explicitly with spark.default.parallelism, it will default
to the number of cores currently available (minimum 2). At the very
start, some executors haven't completed registering, which I think
explains why it goes up after a short time. (In the case of dynamic
allocation it will change over time.) You can set it explicitly to
match what you set the executor count and cores to.

On Mon, Jul 6, 2020 at 10:35 PM Stephen Coy
<s...@infomedia.com.au.invalid> wrote:
>
> Hi there,
>
> I have found that if I invoke
>
> sparkContext.defaultParallelism()
>
> too early it will not return the correct value;
>
> For example, if I write this:
>
> final JavaSparkContext sparkContext = new 
> JavaSparkContext(sparkSession.sparkContext());
> final int workerCount = sparkContext.defaultParallelism();
>
> I will get some small number (which I can’t recall right now).
>
> However, if I insert:
>
> sparkContext.parallelize(List.of(1, 2, 3, 4)).collect()
>
> between these two lines I get the expected value being something like 
> node_count * node_core_count;
>
> This seems like a hacky work around solution to me. Is there a better way to 
> get this value initialised properly?
>
> FWIW, I need this value to size a connection pool (fs.s3a.connection.maximum) 
> correctly in a cluster independent way.
>
> Thanks,
>
> Steve C
>
>
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