scala> Seq((1, "b", "test"), (2, "a", "foo")).toDF("id", "a",
"b").registerTempTable("test")
scala> val df = sql("SELECT struct(id, b, a) from test order by b")
df: org.apache.spark.sql.DataFrame = [struct(id, b, a): struct<id: int, b:
string ... 1 more field>]
scala> df.show
+----------------+
|struct(id, b, a)|
+----------------+
| [2,foo,a]|
| [1,test,b]|
+----------------+
On Sat, Feb 27, 2016 at 10:25 AM, Ashok Kumar <ashok34...@yahoo.com.invalid>
wrote:
> Hello,
>
> I like to be able to solve this using arrays.
>
> I have two dimensional array of (String,Int) with 5 entries say
> arr("A",20), arr("B",13), arr("C", 18), arr("D",10), arr("E",19)
>
> I like to write a small code to order these in the order of highest Int
> column so I will have arr("A",20), arr("E",19), arr("C",18) ....
>
> What is the best way of doing this using arrays only?
>
> Thanks
>
