Philip, the guy is trying to help you. Calling him silly is a bit too far. He might assume your problem is IO bound which might not be the case. If you need only 4 cores per job no matter what there is little advantage to use spark in my opinion because you can easily do this with just a worker farm that take the job and process it in a single machine. let the scheduler figures out which node in the farm is idled and spawns jobs on those until all of them are saturated. Call me silly but this seems much simpler.
Sent from my iPhone > On 3 Oct, 2015, at 12:02 am, Philip Weaver <philip.wea...@gmail.com> wrote: > > You can't really say 8 cores is not much horsepower when you have no idea > what my use case is. That's silly. > >> On Fri, Sep 18, 2015 at 10:33 PM, Adrian Tanase <atan...@adobe.com> wrote: >> Forgot to mention that you could also restrict the parallelism to 4, >> essentially using only 4 cores at any given time, however if your job is >> complex, a stage might be broken into more than 1 task... >> >> Sent from my iPhone >> >> On 19 Sep 2015, at 08:30, Adrian Tanase <atan...@adobe.com> wrote: >> >>> Reading through the docs it seems that with a combination of FAIR scheduler >>> and maybe pools you can get pretty far. >>> >>> However the smallest unit of scheduled work is the task so probably you >>> need to think about the parallelism of each transformation. >>> >>> I'm guessing that by increasing the level of parallelism you get many >>> smaller tasks that the scheduler can then run across the many jobs you >>> might have - as opposed to fewer, longer tasks... >>> >>> Lastly, 8 cores is not that much horsepower :) >>> You may consider running with beefier machines or a larger cluster, to get >>> at least tens of cores. >>> >>> Hope this helps, >>> -adrian >>> >>> Sent from my iPhone >>> >>> On 18 Sep 2015, at 18:37, Philip Weaver <philip.wea...@gmail.com> wrote: >>> >>>> Here's a specific example of what I want to do. My Spark application is >>>> running with total-executor-cores=8. A request comes in, it spawns a >>>> thread to handle that request, and starts a job. That job should use only >>>> 4 cores, not all 8 of the cores available to the cluster.. When the first >>>> job is scheduled, it should take only 4 cores, not all 8 of the cores that >>>> are available to the driver. >>>> >>>> Is there any way to accomplish this? This is on mesos. >>>> >>>> In order to support the use cases described in >>>> https://spark.apache.org/docs/latest/job-scheduling.html, where a spark >>>> application runs for a long time and handles requests from multiple users, >>>> I believe what I'm asking about is a very important feature. One of the >>>> goals is to get lower latency for each request, but if the first request >>>> takes all resources and we can't guarantee any free resources for the >>>> second request, then that defeats the purpose. Does that make sense? >>>> >>>> Thanks in advance for any advice you can provide! >>>> >>>> - Philip >>>> >>>>> On Sat, Sep 12, 2015 at 10:40 PM, Philip Weaver <philip.wea...@gmail.com> >>>>> wrote: >>>>> I'm playing around with dynamic allocation in spark-1.5.0, with the FAIR >>>>> scheduler, so I can define a long-running application capable of >>>>> executing multiple simultaneous spark jobs. >>>>> >>>>> The kind of jobs that I'm running do not benefit from more than 4 cores, >>>>> but I want my application to be able to take several times that in order >>>>> to run multiple jobs at the same time. >>>>> >>>>> I suppose my question is more basic: How can I limit the number of cores >>>>> used to load an RDD or DataFrame? I can immediately repartition or >>>>> coalesce my RDD or DataFrame to 4 partitions after I load it, but that >>>>> doesn't stop Spark from using more cores to load it. >>>>> >>>>> Does it make sense what I am trying to accomplish, and is there any way >>>>> to do it? >>>>> >>>>> - Philip >
