Hi,
You can also use any path pattern as defined here:
http://hadoop.apache.org/docs/r2.2.0/api/org/apache/hadoop/fs/FileSystem.html#globStatus%28org.apache.hadoop.fs.Path%29
e.g.:
sc.textFile('{/path/to/file1,/path/to/file2}')
Christophe.
On 29/04/2014 05:07, Nicholas Chammas wrote:
Not that I know of. We were discussing it on another thread and it came up.
I think if you look up the Hadoop FileInputFormat API (which Spark uses) you'll
see it mentioned there in the docs.
http://hadoop.apache.org/docs/r2.2.0/api/org/apache/hadoop/mapred/FileInputFormat.html
But that's not obvious.
Nick
2014년 4월 28일 월요일, Pat Ferrel<[email protected]<mailto:[email protected]>>
님이 작성한 메시지:
Perfect.
BTW just so I know where to look next time, was that in some docs?
On Apr 28, 2014, at 7:04 PM, Nicholas Chammas
<[email protected]<javascript:_e(%7B%7D,'cvml','[email protected]');>>
wrote:
Yep, as I just found out, you can also provide sc.textFile() with a
comma-delimited string of all the files you want to load.
For example:
sc.textFile('/path/to/file1,/path/to/file2')
So once you have your list of files, concatenate their paths like that and pass
the single string to textFile().
Nick
On Mon, Apr 28, 2014 at 7:23 PM, Pat Ferrel
<[email protected]<javascript:_e(%7B%7D,'cvml','[email protected]');>>
wrote:
sc.textFile(URI) supports reading multiple files in parallel but only with a
wildcard. I need to walk a dir tree, match a regex to create a list of files,
then I’d like to read them into a single RDD in parallel. I understand these
could go into separate RDDs then a union RDD can be created. Is there a way to
create a single RDD from a URI list?
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