No, partition number is determined by the parameter you set in groupByKey,
see
http://spark.apache.org/docs/latest/api/core/index.html#org.apache.spark.rdd.PairRDDFunctions
for details, suggest you reading some docs before ask questions
Joe L wrote
> I was wonder if groupByKey returns 2 partitions in the below example?
>
>>>> x = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])
>>>> sorted(x.groupByKey().collect())
> [('a', [1, 1]), ('b', [1])]
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