Answering my own question here. This may not be efficient, but this is
what I came up with:
rdd1.coalesce(N).glom.zip(rdd2.coalesce(N).glom).map { case(x,y) => x++y}
On Wed, Mar 26, 2014 at 11:11 AM, Walrus theCat <walrusthe...@gmail.com>wrote:
> Hi,
>
> I want to do something like this:
>
> rdd3 = rdd1.coalesce(N).partitions.zip(rdd2.coalesce(N).partitions)
>
> I realize the above will get me something like
> Array[(partition,partition)].
>
> I hope you see what I'm going for here -- any tips on how to accomplish
> this?
>
> Thanks
>
