Oh sorry it is the name of my method… so I built this method
getUsersListByRoomId(long roomId) that return a Map of Users in a room
public HashMap<String, String[]> getUsersListByRoomId(long roomId)
{
HashMap<String, String[]> users = new HashMap<String,String[]>();
try
{
String sessionId = userEndPoint.getSession();
long userId = userEndPoint.loginUser(sessionId,
this.rootUser, this.rootPwd);
if(userId <0)
{//Login Error
return null;
}
else
{
RoomReturn roomObjet =
roomEndPoint.getRoomWithClientObjectsById(sessionId, roomId);
if(roomObjet!= null)
{
RoomUser[] roomUsers =
roomObjet.getRoomUser();
if(roomUsers != null &&
roomUsers.length >0)
{
for(int i = 0;
i<roomUsers.length; i++)
{
users.put(roomUsers[i].getPublicSID(), new String[]{roomUsers[i].getLastname(),
roomUsers[i].getFirstname()});
}
}
}
}
}
catch (RemoteException e)
{
e.printStackTrace();
}
return users;
}
BUT I NEED USERID or EXTERNAL-USERID to be sure of a user….is there a method to
get it?
Da: Maxim Solodovnik [mailto:solomax...@gmail.com]
Inviato: lunedì 3 novembre 2014 19:18
A: Openmeetings user-list
Oggetto: Re: check if user is in a Room
What version are you using? I'm unable to find the method you a referring to
On 3 November 2014 22:52, Dario Guida <produzion...@infotelsistemi.com> wrote:
Hi,
I want to check if a user is in an specificRoom…How can I do?
I’ve seen getUsersListByRoomId(roomId) but It return “firstName”, “lastName”,
“publicSID” of each user… I need userId or externalUserId to be sure of a
specific user.
Thank you
--
WBR
Maxim aka solomax
