Hi Qing,
> am I right to think that there will be 1 reduce function per key, and
they will never overlap?

I agree with this, please correct me if I'm wrong.  For a certain key, it
will be divided into a certain key group range, and thus sent to a certain
sub-task(reduce function instance). A key is only processed by one sub-task
of an operator, so the subtasks of one key don't overlap.  But in turn, a
subtask will process multiple keys.
For example: if we have many pairs like: (k1,v11), ... (k2,v2) ... (k1,v12)
...(k3,v3) ... (k1,v13),...   v12 is always processed after v11.

Best,
Yanfei

Qing Lim <q....@mwam.com> 于2022年11月3日周四 16:17写道:

> Hi Yanfei
>
> Thanks for the explanation.
>
>
>
> If I use reduce in the context of keyed stream with window, am I right to
> think that there will be 1 reduce function per key, and they will never
> overlap? Each reduce function instance will only receive elements from the
> same key in order.
>
>
>
> *From:* Yanfei Lei <fredia...@gmail.com>
> *Sent:* 03 November 2022 03:06
> *To:* Qing Lim <q....@mwam.com>
> *Cc:* User <user@flink.apache.org>
> *Subject:* Re: Does reduce function on keyed window gives any guarantee
> on the order of elements?
>
>
>
> Hi Qing,
>
> > Does it guarantee that it will be called in the same order of elements
> in the stream, where value2 is always 1 element after value1?
>
>
> Order is maintained within each parallel stream partition. If the reduce
> operator only has one sending- sub-task, the answer is YES, but if reduce
> operator has multiple sending- sub-task, order among elements is only
> preserved for each pair of sending- and receiving tasks.
>
> The answers under
> https://stackoverflow.com/questions/38354713/ordering-of-records-in-stream 
> might
> help.
>
> Best,
>
> Yanfei
>
>
>
> Qing Lim <q....@mwam.com> 于2022年11月3日周四 01:32写道:
>
> Hi, Flink User Group
>
>
>
> I am trying to use Reduce function, I wonder does it guarantee order when
> its called?
>
>
>
> The signature is as follow:
>
>
>
> T reduce(T value1, T value2) throws Exception;
>
>
>
> Does it guarantee that it will be called in the same order of elements in
> the stream, where value2 is always 1 element after value1?
>
>
>
> Kind regards
>
>
>
>
>
> *Qing Lim *| Marshall Wace LLP, George House, 131 Sloane Street, London | 
> E-mail:
> q....@mwam.com | Tel: +44 207 925 4865
>
>
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-- 
Best,
Yanfei

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