Hi, thank you for your reply Actually, I'm doing something very similar to your code. The problem I'm having is that this structure is not generating any loop. For instance, If I print *labelsVerticesGroup*, I only see the initial set of tuples, the one from *updated**LabelsVerticesGroup* (at the end of the first iteration) and nothing more. So, it means that the content of *updated* *LabelsVerticesGroup* is indeed being correctly assigned to *labelsVerticesGroup*, but the loop itself is not happening.
For simplicity sake, here I'm omitting the logic behind the separation of the tuples that need to be fed back to the loop. I do understand that both codes we commented here are expected to loop indefinitely. On the complete version of mine, I use the JoinFunction, a ProcessAllWindowFunction, a Filter Function and a Map to create a flag that indicates if there was a change on the label of a vertex during the join function, then the ProcessAllWindowFunction to spread this flag to the whole window, in case any tuple had a change. Finally I filter the tuples by this flag. This whole mechanism is separating the tuples as expected. However, even if I remove this logic from the code, in order to get an infinite loop of the tuples (as we get on the code we've written in the previous emails), the iteration does not work. PS. I've been using Flink 1.3.3 Best, Henrique Em sex, 11 de mai de 2018 às 00:01, Rong Rong <walter...@gmail.com> escreveu: > Based on the pseudo code. Seems like you are trying to do the loop by > yourself and not suing the iterative.map() function[1]. > > I think you would need to specify the "map" function in order to use the > iterative stream. and there should be a clear definition on > which data is iterative. In this case you have label & vertices > interlacing each other but no specific loop back. > > I would suggest something close to the example in [1], like > *labelsVerticesGroup* = DataStream<initial_label, *vertices*> > > *labels* = *labelsVerticesGroup*.map(...) > .keyBy(VertexID) > .window(...) > .min(label); > > *vertices* = *labelsVerticesGroup*.map(...) > > *updatedLabelsVerticesGroup* = *vertices*.join(*labels* > ).where(VertexId).equalTo(VertexId) > .windowAll(...) > .agg(...) > > *labelsVerticesGroup*.closeWith(*updatedLabelsVerticesGroup**)* > > Is this what you are looking for? > > -- > Rong > > Reference: > [1] > https://ci.apache.org/projects/flink/flink-docs-master/dev/datastream_api.html#iterations > > On Thu, May 10, 2018 at 9:50 AM, Henrique Colao Zanuz < > henrique.co...@gmail.com> wrote: > >> Hi, >> >> I am trying to implement a connected components algorithm using >> DataStream. For this algorithm, I'm separating the data by tumbling >> windows. So, for each window, I'm trying to compute it independently. >> This algorithm is iterative because the labels (colors) of the vertices >> need to be propagated. Basically, I need to iterate over the following >> steps: >> >> Input: *vertices *= Datastream of <VertexId, [list of neighbor >> vertices], label> >> >> Loop: >> *labels *= *vertices*.flatmap (emiting a tupple <VertexID, label> >> for every vertices.f0 and every element on vertices.f1) >> .keyBy(VertexID) >> .window(...) >> .min(label); >> >> *updatedVertices *= *vertices*. >> join(labels).where(VertexId).equalTo(VertexId) >> .windowAll(...) >> .apply(re-emit original *vertices *stream >> tuples, but keeping the new labels) >> >> End loop >> >> I am trying to use IterativeStreams to do so. However, despite >> successfully separating the tuples that need to be fed back to the loop (by >> using filters and closeWith), the subsequent iterations are not happening. >> So, what I get is only the first iteration. >> I suppose this might come from the fact that I'm creating a new stream >> (labels) based on the original IterativeStream, joining it with the >> original one (vertices) and only then closing the loop with it. >> Do you know whether Flink has some limitation in this respect? and if so, >> would you have a hint about a different approach I could take for this >> algorithm to avoid this? >> >> thank you in advance, >> Henrique Colao >> >> >> >
