Cool :-) We should add this tip to the documentation of the project operator. I'll open a JIRA for that.
2015-04-17 5:41 GMT-05:00 Flavio Pompermaier <pomperma...@okkam.it>: > That worked like a charm! > > Thanks a lot Fabian! > > On Fri, Apr 17, 2015 at 12:37 PM, Fabian Hueske <fhue...@gmail.com> wrote: > >> The problem is cause by the project() operator. >> The Java compiler does infer its return type and defaults to Tuple. >> >> You can help the compiler like this: >> >> DataSet<Tuple1<String>> ds2 = ds.<Tuple1<String>project(0).distinct(0); >> >> >> 2015-04-17 4:33 GMT-05:00 Flavio Pompermaier <pomperma...@okkam.it>: >> >> I have errors in Eclipse doing something like: >>> >>> DataSet<Tuple5<String,String,String,String,String>> ds = .... >>> DataSet<Tuple1<String>> ds2 = .ds.project(0).distinct(0); >>> >>> It says that I have to declare ds2 as a Dataset<Tuple> >>> >>> On Fri, Apr 17, 2015 at 11:15 AM, Maximilian Michels <m...@apache.org> >>> wrote: >>> >>>> Hi Flavio, >>>> >>>> Do you have an exapmple? The DistinctOperator should return a typed >>>> output just like all the other operators do. >>>> >>>> Best, >>>> Max >>>> >>>> On Fri, Apr 17, 2015 at 10:07 AM, Flavio Pompermaier < >>>> pomperma...@okkam.it> wrote: >>>> >>>>> Hi guys, >>>>> >>>>> I'm trying to make (in Java) a project().distinct() but then I cannot >>>>> create the generated dataset with a typed tuple because the distinct >>>>> operator returns just an untyped Tuple. >>>>> Is this an error in the APIs or am I doing something wrong? >>>>> >>>>> Best, >>>>> Flavio >>>>> >>>> >>>> >>> >>> >>> >
