Re: RelationshipQuery

[Andrus Adamchik]

You are. A regular SelectQuery should work. You can use relationship  
path to qualify on FK. E.g.

int id = ..;
ExpressionFactory.matchExp("artist", id);
Andrus


On Apr 26, 2010, at 2:32 PM, Joe Baldwin wrote:

I asked this question previously but did not see a reply.


I am trying to create a very fast custom fetch that is essentially a  
qualified relationship.  My relationships are based on an integer  
"oid" field.

Can I use the RelationshipQuery and qualify it? Or am I on the wrong  
track?