It seems, that we can compare UUID s and find the biggest or smallest On Tue, 21 May 2019 at 11:15, Aleksey Korolkov <korolko...@gmail.com> wrote:
> Unfortunately not, I had the same idea, but it is not timeuuid, an example > from my cluster (5edde338-ce0d-3ead-bbee-63010ffbee6d) > > On Tue, 21 May 2019 at 10:40, Rhys Campbell > <rhys.james.campb...@googlemail.com.invalid> wrote: > >> I'd hazzard a guess that the uuid contains a datetime component >> >> Aleksey Korolkov <korolko...@gmail.com> schrieb am Di., 21. Mai 2019, >> 09:36: >> >>> Thanks for the feedback. >>> I also think that node choose like "last wins" but I could not find any >>> timestamp of schema creation in system tables. >>> Hope this is not the order of an element in Map or List) >>> >>> >>> On Tue, 21 May 2019 at 02:58, Stefan Miklosovic < >>> stefan.mikloso...@instaclustr.com> wrote: >>> >>>> My guess is that the "latest" schema would be chosen but I am >>>> definitely interested in in-depth explanation. >>>> >>>> On Tue, 21 May 2019 at 00:28, Alexey Korolkov <korolko...@gmail.com> >>>> wrote: >>>> > >>>> > Hello team, >>>> > In some circumstances, my cluster was split onto two schema versions >>>> > (half on one version, and rest on another) >>>> > In the process of resolving this issue, I restarted some nodes. >>>> > Eventually, nodes migrated to one schema, but it was not clear why >>>> they choose exactly this version of schema? >>>> > I haven't found any explainings of the factor on which they picking >>>> schema version, >>>> > please help me to find out the algorithm of choosing schema or >>>> classes in source code responsible for this. >>>> > >>>> > >>>> > >>>> > >>>> > >>>> > -- >>>> > Sincerely yours, Korolkov Aleksey >>>> >>>> --------------------------------------------------------------------- >>>> To unsubscribe, e-mail: user-unsubscr...@cassandra.apache.org >>>> For additional commands, e-mail: user-h...@cassandra.apache.org >>>> >>>> >>> >>> -- >>> *Sincerely yours, **Korolkov Aleksey* >>> >> > > -- > *Sincerely yours, **Korolkov Aleksey* > -- *Sincerely yours, **Korolkov Aleksey*
