You are welcome! )
>recent ten movies watched by the user within 30 days.
In this case you can't use PRIMARY KEY (user_name, video_id), as video_id is
demanded to fetch row, so all this stuff may be
CREATE TYPE play (video_id text, position int, last_time timestamp);
CREATE TABLE recent (user_name text PRIMARY KEY, play_list
LIST<frozen<play>>);
You can easily retrieve play list for specific user by his ID. Instead of LIST
you can use MAP, I don't think that for ten entries it matters.
Best regards, Vladimir Yudovin,
Winguzone - Hosted Cloud Cassandra
Launch your cluster in minutes.
---- On Tue, 08 Nov 2016 22:29:48 -0500ben ben <diamond....@outlook.com>
wrote ----
Hi Vladimir Yudovin,
Thank you very much for your detailed explaining. Maybe I didn't describe
the requirement clearly. The use cases should be:
1. a user login our app.
2. show the recent ten movies watched by the user within 30 days.
3. the user can click any one of the ten movie and continue to watch from the
last position she/he did. BTW, a movie can be watched several times by a user
and the last positon is needed indeed.
BRs,
BEN
发件人: Vladimir Yudovin <vla...@winguzone.com>
发送时间: 2016年11月8日 22:35:48
收件人: user
主题: Re: A difficult data model with C*
Hi Ben,
if need very limited number of positions (as you said ten) may be you can store
them in LIST of UDT? Or just as JSON string?
So you'll have one row per each pair user-video.
It can be something like this:
CREATE TYPE play (position int, last_time timestamp);
CREATE TABLE recent (user_name text, video_id text, review
LIST<frozen<play>>, PRIMARY KEY (user_name, video_id));
UPDATE recent set review = review + [(1234,12345)] where user_name='some user'
AND video_id='great video';
UPDATE recent set review = review + [(1234,123456)] where user_name='some user'
AND video_id='great video';
UPDATE recent set review = review + [(1234,1234567)] where user_name='some
user' AND video_id='great video';
You can delete the oldest entry by index:
DELETE review[0] FROM recent WHERE user_name='some user' AND video_id='great
video';
or by value, if you know the oldest entry:
UPDATE recent SET review = review - [(1234,12345)] WHERE user_name='some user'
AND video_id='great video';
Best regards, Vladimir Yudovin,
Winguzone - Hosted Cloud Cassandra
Launch your cluster in minutes.
---- On Mon, 07 Nov 2016 21:54:08 -0500ben ben <diamond....@outlook.com>
wrote ----
Hi guys,
We are maintaining a system for an on-line video service. ALL users' viewing
records of every movie are stored in C*. So she/he can continue to enjoy the
movie from the last point next time. The table is designed as below:
CREATE TABLE recent (
user_name text,
vedio_id text,
position int,
last_time timestamp,
PRIMARY KEY (user_name, vedio_id)
)
It worked well before. However, the records increase every day and the last ten
items may be adequate for the business. The current model use vedio_id as
cluster key to keep a row for a movie, but as you know, the business prefer to
order by the last_time desc. If we use last_time as cluster key, there will be
many records for a singe movie and the recent one is actually desired. So how
to model that? Do you have any suggestions?
Thanks!
BRs,
BEN
