On Mon, 24 Feb 2014 19:14:48 +0000 Ben Hood <0x6e6...@gmail.com> wrote:
> So I have a question about the encoding of 0: \x00\x00\x00\x00\x00. The first four octets are the decimal shift (0), and the remaining ones (one in this case) encode a varint - 0 in this case. So it's 0 * 10**0 literally zero. Technically the decimal shift matters not for zero - any four bytes could be given as the shift, ending in \x00, but 0 is the simplest. -- Paul "LeoNerd" Evans leon...@leonerd.org.uk ICQ# 4135350 | Registered Linux# 179460 http://www.leonerd.org.uk/
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