If I execute the above query from CQL shell, it doesn't work for me at
all... This is what I get -
cqlsh:pp> insert into test_new (employee_id, employee_name, value,
last_modified_date) values ('1', 'e29', 'some_new_value', now()) if not
exists
;
Bad Request: line 1:123 missing EOF at 'if'
Is there anything I am missing here? I am running Cassandra 1.2.3
On Fri, Nov 8, 2013 at 5:33 AM, DuyHai Doan <doanduy...@gmail.com> wrote:
> Consider using the new lightweight transaction
>
> insert into test_new (employee_id, employee_name, value,
> last_modified_date) values ('1', 'e29', 'some_new_value', now()) *if not
> exists*;
>
>
>
> Le vendredi 8 novembre 2013 03:53:12 UTC+1, Techy Teck a écrit :
>
>> I am using the below table in our use case -
>>
>> create table test_new (
>> employee_id text,
>> employee_name text,
>> value text,
>> last_modified_date timeuuid,
>> primary key (employee_id, last_modified_date)
>> );
>>
>> create index employee_name_idx on test_new (employee_name);
>>
>> In my above table employee_id will be unique always starting from 1 till
>> 32767. So our query pattern is like this -
>>
>> 1. Give me everything for any of the employee_id?
>> 2. Give me everything for what has changed in last 5 minutes?
>> 3. Give me everything for any of the employee_name?
>>
>>
>> I will be inserting below data into my above table -
>>
>> insert into test_new (employee_id, employee_name, value,
>> last_modified_date) values ('1', 'e27', 'some_value', now());
>> insert into test_new (employee_id, employee_name, value,
>> last_modified_date) values ('2', 'e27', 'some_new_value', now());
>> insert into test_new (employee_id, employee_name, value,
>> last_modified_date) values ('3', 'e28', 'some_new_again_value', now());
>>
>> So now is there any way to avoid this particular scenario in my above
>> table for the below query.. Somehow somebody by mistake is trying to
>> execute the below query then it will create another row with employee_id as
>> 1 and with other fields? I don't want anyone to insert the same employee_id
>> again if it is already there in the cassandra database.. Any thoughts?
>>
>> insert into test_new (employee_id, employee_name, value,
>> last_modified_date) values ('1', 'e29', 'some_new_value', now());
>>
>>
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