The DS docs go with "should" regarding setting the initial token to zero. It's not a "must," but you get enough convenience out of never having to move tokens on that node that I'm not sure why you wouldn't do it.
If anyone has a compelling reason not to do so, I'm happy to hear it :) On Fri, Apr 1, 2011 at 10:58 AM, Edward Capriolo <edlinuxg...@gmail.com>wrote: > On Fri, Apr 1, 2011 at 1:15 PM, Peter Schuller > <peter.schul...@infidyne.com> wrote: > >> Now, I moved the tokens. I still observe that read latency deteriorated > with > >> 3 machines vs original one. Replication factor is 1, Cassandra version > 0.7.2 > >> (didn't have time to upgrade as I need results by this weekend). > > > > Read *latency* is fully expected to increase if you just add a node. > > *Throughput* should increase, unless you have a workload that manages > > to be more expensive on RPC than actual reads/writes. > > > > Latency would only be improved by additional nodes under some significant > load. > > > > How are you benchmarking? Are you concurrently submitting requests to > > all nodes at the same time? Try using stress.py from the Cassandra > > tree as a comparison. > > > > If you're sending one request at a time, there is no expectation at > > all of a performance improvement - just a decrease in performance. > > > > -- > > / Peter Schuller > > > > To be clear on this issue. It does not matter where the tokens start > it only matters that they are equally spaced around the token space. > > So for a 4 node clusters your tokens should either be > 1 * ((2^127) / 4) = 42535295865117307932921825928971026432 > 2 * ((2^127) / 4) = 85070591730234615865843651857942052864 > 3 * ((2^127) / 4) = 127605887595351923798765477786913079296 > 4 * ((2^127) / 4) = 170141183460469231731687303715884105728 > > or > 0 * ((2^127) / 4) = 0 > 1 * ((2^127) / 4) = 42535295865117307932921825928971026432 > 2 * ((2^127) / 4) = 85070591730234615865843651857942052864 > 3 * ((2^127) / 4) = 127605887595351923798765477786913079296 > > If you move one you have to move the rest because the distance between > 170141183460469231731687303715884105728 and 0 is 1 >