Hi all, I've got cassandra superlcolumn looking like that:
<ColumnFamily Name="users" CompareWith="TimeUUIDType" ColumnType="Super" CompareSubcolumnsWith="BytesType" /> now in this columnfamily I've inserted something like that: ["client"] => array(1) { ["2a3909c0-a612-11df-b27e-346336336631"]=> array(3) { ["add_date"]=> string(10) "1281618279" ["lastname"]=> string(8) "blablabla" ["name"]=> string(6) "myname" } } my question is, how to get from "client" this one "2a3909c0-a612-11df- b27e-346336336631" column? I was tryin to get->('client', '2a3909c0- a612-11df-b27e-346336336631') - but with no results... maybe I should convert this "2a3909c0-a612-11df-b27e-346336336631" somehow before I put it to get() ? or maybe I'm thinking wrong way... regards -- View this message in context: http://cassandra-user-incubator-apache-org.3065146.n2.nabble.com/how-to-retrieve-data-from-supercolumns-by-phpcassa-tp5416141p5416141.html Sent from the cassandra-u...@incubator.apache.org mailing list archive at Nabble.com.