Hi, > If you use random partitioning, you can loop through all keys with a range > query, but they will not be sorted. > > True or False?
I think they will be sorted in a way of MD5 hash if you use RandomPartitioner, at least I looked into SSTables and RandomPartitioner#getToken. On Sun, May 9, 2010 at 4:00 PM, David Boxenhorn <da...@lookin2.com> wrote: > This is something that I'm not sure that I understand. Can somebody > confirm/deny that I understand it? Thanks. > > If you use random partitioning, you can loop through all keys with a range > query, but they will not be sorted. > > True or False? > > On Sat, May 8, 2010 at 3:45 AM, AJ Chen <ajc...@web2express.org> wrote: >> >> thanks, that works. -aj >> >> On Fri, May 7, 2010 at 1:17 PM, Stu Hood <stu.h...@rackspace.com> wrote: >>> >>> Your IPartitioner implementation decides how the row keys are sorted: see >>> http://wiki.apache.org/cassandra/StorageConfiguration#Partitioner . You need >>> to be using one of the OrderPreservingPartitioners if you'd like a >>> reasonable order for the keys. >>> >>> -----Original Message----- >>> From: "AJ Chen" <ajc...@web2express.org> >>> Sent: Friday, May 7, 2010 3:10pm >>> To: user@cassandra.apache.org >>> Subject: key is sorted? >>> >>> I have a super column family for "topic", key being the name of the >>> topic. >>> <ColumnFamily Name="Topic" CompareWith="UTF8Type" ColumnType="Super" >>> CompareSubcolumnsWith="BytesType" /> >>> When I retrieve the rows, the rows are not sorted by the key. Is the row >>> key >>> sorted in cassandra by default? >>> >>> -aj >>> -- >>> AJ Chen, PhD >>> Chair, Semantic Web SIG, sdforum.org >>> http://web2express.org >>> twitter @web2express >>> Palo Alto, CA, USA >>> >>> >> >> >> >> -- >> AJ Chen, PhD >> Chair, Semantic Web SIG, sdforum.org >> http://web2express.org >> twitter @web2express >> Palo Alto, CA, USA > > -- ============================= Shinpei Ohtani mail : shinpei.oht...@gmail.com blog : http://d.hatena.ne.jp/shot6/ twitter : http://twitter.com/shot6 =============================
