I understand, but there isn't a way to define a data schema, and get it sorted in the insertion,so then the natural order would match what I need to query?
2010/3/22 Jonathan Ellis <jbel...@gmail.com> > You have to fetch the columns and sort client-side, for now. > > 2010/3/22 Juan Manuel García del Moral <juanman...@taringa.net>: > > Hello > > > > I have this: > > > > get SocialAds.Anonimos['3539792']; > > => (super_column=Tag, > > (column=1036, value=5, timestamp=1001181414) > > (column=116, value=2, timestamp=1001181414) > > (column=121988, value=2, timestamp=1001181413) > > (column=13838, value=3, timestamp=1001181416) > > (column=14105, value=2, timestamp=1001181413) > > (column=169095, value=2, timestamp=1001181414) > > (column=30253, value=2, timestamp=1001181413) > > (column=350737, value=1, timestamp=1001181341) > > (column=350738, value=1, timestamp=1001181341)) > > > > I would need to get the column with the highest value for that CF, this > is > > something I have to do in the get() or in the data schema? > > > > my schema is: > > > > <Keyspace Name="SocialAds"> > > > > <ColumnFamily ColumnType="Super" > > CompareWith="UTF8Type" > > CompareSubcolumnsWith="UTF8Type" > > Name="Anonimos" > > RowsCached="1000" > > KeysCached="50%" > > Comment="A column family with supercolumns, whose > column > > and subcolumn names are UTF8 strings"/> > > > > > <ReplicaPlacementStrategy>org.apache.cassandra.locator.RackUnawareStrategy</ReplicaPlacementStrategy> > > <ReplicationFactor>1</ReplicationFactor> > > > > > <EndPointSnitch>org.apache.cassandra.locator.EndPointSnitch</EndPointSnitch> > > </Keyspace> > > > > > > Any ideas? > > > > Thanks in advance > > > > Juan > > > > >
