Try the "dirname" task. This will normalize a file name, but it will
also give it the full directory path and not the relative path:
<property name="file.name"
value="this/that/the-other/../../is/a/test.txt"/>
<dirname property="dirname" file="${file.name}/FOO"/>
<echo message="This is the path: ${dirname}"/>
will print out: "/home/dweintraub/this/is/a/test.txt".
Notice I appended "FOO" on the path, so <dirname> would also include
the file name too.
On Wed, Mar 25, 2009 at 1:51 AM, jbmdharris <jbmdhar...@hotmail.com> wrote:
>
> Does anyone have any good examples of normalizing paths in files?
>
> I have files that have paths like this in them:
>
> ../../foo.htm
>
> Which I process to make fully-qualified like this:
>
> /abc/def/ghi/jkl/mno/../../foo.htm
>
> Now I want to normalize the fully-qualified paths to remove the "../" parts
> to get a result like this:
>
> /abc/def/ghi/foo.htm
>
> I've found I can use <replaceregexp> like this to replace one set of "../"
> pairs:
>
> <replaceregexp
> match="${util.includeTagStartRegExp}(.*?)/([^/.]*?)/\.\./(.*?)${util.includeTagEndRegExp}"
> replace="${util.includeTagStartRegExp}\1/\3${util.includeTagEndRegExp}"
> flags="sg" byline="false">
>
> And if I enclose this in a for loop, I can call it multiple times to remove
> multiple sets of "../" pairs. However, I don't like hardcoding the number
> of loops. Because it would be complicated to actually scan the files to get
> the maximum number of "../" path components, the simplest thing for me to
> use as my loop count is the maximum depth of the directory tree. Is there a
> way to compute this?
>
> I've tried looping over the directory tree, getting the directories,
> stripping out everything that isn't a "/". However, I can't figure out how
> to determine which of these strings is the longest inside a for loop so I
> know what my loop count will be.
>
> --
> View this message in context:
> http://www.nabble.com/Normalizing-paths-in-files-tp22695672p22695672.html
> Sent from the Ant - Users mailing list archive at Nabble.com.
>
>
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--
--
David Weintraub
qazw...@gmail.com
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