pathsep="${line.separator}"
--- Ben Tu <[EMAIL PROTECTED]> wrote:
> Matt,
> This will returned the list of files separate with
> path separator.
> I want it returns a list of files as follow.
>
> ${basedir}/com/abc/a.class
> ${basedir}/com/abc/b.class
>
> Thanks, Ben
>
>
> -----Original Message-----
> From: Matt Benson [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, October 07, 2008 10:35 AM
> To: Ant Users List
> Subject: Re: find file in specify directory and its
> sub-directory
>
> Are your sed commands trying to strip off the
> leading
> ./ , then escape dollar signs found? If so, the
> second probably wouldn't be relevant:
>
> <pathconvert>
> <fileset dir="${basedir}" includes="**/*.class" />
> <globmapper from="${basedir}/*" to="*" />
> </pathconvert>
>
> Something like that?
>
> HTH,
> Matt
>
> --- Ben Tu <[EMAIL PROTECTED]> wrote:
>
> > Hi,
> > I would like to accomplish the similar task below
> in
> > ant script.
> > Does anyone know how?
> >
> > find . -name '*.class' | sed -e 's/^.\///g' -e
> > 's/\$/\\\$/g' | sort > log.txt
> >
> > thanks
> >
> >
>
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>
>
>
>
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