You may want to look at the <sortlist> task (part of
the ant-contrib project).
If you are happy with sorting the files based upon the
name you can try the following (it is what we do):
<path id="builds">
<dirset
dir="${release.root}/Build_v${current.version.number}">
<include
name="Build_v${current.version.number}*"/>
</dirset>
</path>
<sortlist property="sorted.builds"
refid="builds"/>
<propertyregex property="max.build.number"
input="${sorted.builds}"
regexp="([0-9]*)$"
select="\1"/>
Have fun...
--- "Schulpen, D.P.H." <[EMAIL PROTECTED]>
wrote:
> I'm trying to write a script to automate certain
> parts of unzipping the most recent build archive of
> an application (in this case NetBeans) in a certain
> location.
>
> However, I can't figure out a way to determine the
> most recent file. I thought about uptodate.
> Unfortunately, I have no idea how to run the task
> for every file in a list against all other files in
> the list, and determine which one returns true. I
> could also use lexical sorting or min/max-ing on the
> filename, but can't seem to find a task that
> supports this.
>
> Some mailing list archive browsing seemed to hint
> that what I'm trying to achive is not yet possible
> with 1.6.5. Is this correct? If not, any pointers?
>
>
> - Daan
>
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