Hi,
Can we compile and run UML kernel on a 64bit Machine? If no, Is
mandatory to give SUBARCH=i386(or some other subarchitecture) when we
compile UML on 64bit Machine?
I'm getting following Kernel panic on execution of UML (built with
SUBARCH=i386). Can anyone point where I went wrong?
######################################
Modules linked in:
Pid: 1, comm: swapper Not tainted 2.6.18.6
RIP: 0033:[<0000002a957a3be7>]
RSP: 0000002a959bffd0 EFLAGS: 00000212
RAX: 0000000000000000 RBX: 00000000000065c5 RCX: ffffffffffffffff
RDX: 0000000000000000 RSI: 0000000000000013 RDI: 00000000000065c5
RBP: 00000000000065c1 R08: 0000000000000000 R09: 0000000000000000
R10: 0000000000000000 R11: 0000000000000212 R12: 0000002a959bf000
R13: 0000007fbffff2a8 R14: 0000007fbffff4c8 R15: 0000007fbffff510
Call Trace:
60fc3ba8: [<60016e4a>] panic_exit+0x2a/0x50
60fc3bb8: [<60040c60>] notifier_call_chain+0x20/0x40
60fc3bc8: [<60010f30>] init+0x0/0x170
60fc3bd8: [<6003036f>] panic+0xcf/0x170
60fc3bf8: [<60084608>] do_execve+0x1d8/0x230
60fc3c38: [<600117c4>] execve1+0x24/0x80
60fc3c68: [<6001182a>] um_execve+0xa/0x50
60fc3c78: [<6008b4b9>] dupfd+0x79/0xb0
60fc3c88: [<60010ef9>] run_init_process+0x49/0x80
60fc3cb8: [<60011029>] init+0xf9/0x170
60fc3cd8: [<60023d3e>] run_kernel_thread+0x4e/0x60
60fc3cf8: [<60010f30>] init+0x0/0x170
60fc3d88: [<6002bd92>] schedule_tail+0x32/0x130
60fc3dd8: [<6001758d>] new_thread_handler+0xdd/0x140
#######################################
Vishal Soni.
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