On 10/05/05, Nik <[EMAIL PROTECTED]> wrote:
Can someone please clear up a misunderstanding of mine please?
In a webpage on kernel 2.6, (http://www.kniggit.net/wwol26.html) I read the following:
> Virtualizing Linux > > One of the most interesting new features in Linux 2.6 is its inclusion > of a "user-mode" architecture.
Does anyone know what is being referred to here? Does this mean that some of all of the UML code has been included in the stock 2.6 kernel? Does it mean I don't have to install UML if I'm using a 2.6 kernel? Alternatively, does this mean that stock 2.6 kernels have all the hooks in them to be a host/guest OS in UML? Or does it simply mean the author is mistaken?
Any clarification would be most welcome.
Cheers! Nik
I'll try and answer your question in a round about way.
UML source code is included in the 2.6.x kernel. The later the version you get the better the support. It is worthwhile getting the latest patches from Jeff Dike or Paolo - links are on UML webpages.
You can host straight out of the boxes on most distributions but they don't give the best performance as run in what is called TT mode although I personally have found it OK. If you recompile and turn on SKAS it makes a better host although make sure you patch as the default has some issues.
Guests are built as a separate architecture e.g. make ARCH=um. This is what they mean - source code is there for normal machines and virtual machines.
Lastly it is user mode as you don't have to have kernel/root priviledges to run a UML kernel as guest. (If you are using for production use you probably shouldn't actually!)
Hope this helps a little.
Ian
Wow! Thank you for the speedy response!
Ian McDonald wrote:
I'll try and answer your question in a round about way.
Your answers were very helpful, thank you very much.
Cheers! Nik.
Barry, Christopher wrote:
But not to us, because it was snipped.
How strange - Ian's original reply was CCed to the list, so I was trying to do the "right thing (tm)", by preserving bandwidth.
Cheers! Nik.
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