On 19/02/14 17:42, Earthednet-wp wrote:
What about:
Replace char 1 of mystring with ""
delete char 1 of $string works; that is not the problem.
Richmond.
Bill
William Prothero
http://es.earthednet.org
On Feb 19, 2014, at 4:28 AM, Richmond <richmondmathew...@gmail.com> wrote:
On 19/02/14 14:09, John Dixon wrote:
as in something like this...
put char 2 to (the number of chars of fld 1) of fld 1 into fld 2
Oddly enough THIS works:
put fld "INN" into $INN
delete char 1 of $INN
put $INN into fld "OWT"
BUT, BUT, BIG UNCOMFORTABLE BUT, this:
put fld "INN" into $INN
put fld "URTEXT" into $URTEXT
repeat until $URTEXT is empty
if $INN contains the first char of $URTEXT then
put the first char of $URTEXT after $OUTTEXT
delete the first char of $URTEXT
else
delete the first char of $URTEXT
end if
end repeat
put $OUTTEXT into fld "fOUTTEXT"
Maybe this is because one cannot use CONTAINS with a string variable, Dunno.
Richmond.
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