I'm not sure to understand your question correctly.

if your array has four "first level" elements: myArray["a"]    myArray["b"]    
myArray["c"]    myArray["d"] 
and that e.g. myArray["c"] has three "second level" elements myArray["c"]["x"]  
  myArray["c"]["y"]    myArray["c"]["z"]
which in turn contain several "third level" elements, e.g. myArray["c"]["y"][1] 
  myArray["c"]["y"][2]   myArray["c"]["y"][3]

you can perfectly well <   put myArray["c"]["y"] into NewArray   > , which will 
have elements NewArray[1]  NewArray [2]   NewArray[3]

NewArray[2] and myArray["c"]["y"][2] will have the same content. And after 
changing these contents (you can even replace them by other arrays) you can do 
the reverse

put newArray into myArray["c"]["y"]

oh, I didn't see that you got answers already - Colin's says the same thing 
more concisely - well I send this one nevertheless. To answer your question 
rather than to read your answer is such an exceptional situation I'll not miss 
it ;-)

Jacques



Le 16 juin 2013 à 21:26, J. Landman Gay <jac...@hyperactivesw.com> a écrit :

> I have a big array with lots of dimensions. Sometimes I need to work with a 
> "sub-dimension" only. For example:
> 
> array[a][b][c][d]
> 
> Each of those elements contains many other elements:
> 
> [c][x][y][z]
> 
> 
> which each contain more elements:
> 
> [c][x][1][2][3]
> 
> Suppose I only want to work with [c][x] and all its sub-dimensions. Is there 
> an efficient way to extract that into its own array without looping through 
> all the [c] keys?
> 
> -- 
> Jacqueline Landman Gay         |     jac...@hyperactivesw.com
> HyperActive Software           |     http://www.hyperactivesw.com
> 
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