Obviously you could do this inline, but then it wouldn't be reusable. I'd go with a function:
function roundUp x,i -- rounds x up to the next i return ((x - .00001) div i + 1) * i end roundUp function test T1,T2 -- returns the difference between two times in seconds -- rounded up to the next 15 minutes convert T1 to seconds convert T2 to seconds put roundUp(T2 - T1,900) into D return D end test The roundUp function will take any two numbers and return the first rounded up to the nearest increment of the second. Obviously the .0000001 aspect is a limitation -- if I were being particular I suppose I'd use an if statement there, but you wanted math and this seems good enough. So: put roundUp(60,10) -- puts 60 put roundUp(61,10) -- puts 70 Having this function makes it easy to do the time math you were talking about, as shown in the test function. gc _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode
