How fast is this with your list?:
on mouseUp
repeat for each line tLine in yourList
add 1 to dupCounter[tLine]
end repeat
combine dupCounter with return and comma
put dupCounter into yourOutputContainer
end mouseUp
Craig Newman
-----Original Message-----
From: Roger Eller <roger.e.el...@sealedair.com>
To: How to use LiveCode <use-livecode@lists.runrev.com>
Sent: Wed, Sep 28, 2011 6:53 pm
Subject: Counting and numbering duplicates in a list
There are several ways I could approach this, but I'm unsure which way is
best? I have a list of numbers that 'may' contain duplicates. I need to
sequence ONLY the duplicates without changing the order the list. If there
is only one, it does not need to be sequenced.
Should I just repeat, and keep the content of line x in a variable, then add
1 to a sequence variable if the number is encountered again? Is there a
better way? Simple stuff, I know, but these lists can be really long, and I
want it to process as quickly possible.
12345
12345
12344
12333
10112
12333
must become:
12345-1
12345-2
12344
12333-1
10112
12333-2
˜Roger
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