On 1 Sep 2011, at 14:16, Dave Cragg wrote:

> It seems using any key on an existing array will produce an empty value. (I 
> don't know if that's how it should behave. I guess the alternative would be 
> throwing an error.)
Update: it seems the array doesn't even need to exist. This also produces the 
same result:

put "A" into theArray[1]
put "B" into theArray[2]
put "C" into theArray[3]
delete variable theArray[2]
put theArray[1] &"*"&otherArray[7] &"*"& theArray[3]


Cheers
Dave



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