I'll have a try - though it's in R, not Python - and I've never used R -)
constant alpha = 2
constant n = 1000
-- x, y are arrays - initialised to 0 already for LC, so no need for "rep"
repeat with i = 2 to n
-- runif(1) returns a random between 0 and 1, so do something similar
put (random(10000) / 10000) * 2 * pi into theta
put (random(10000) / 10000) ^ (-1/alpha) into f
put x[i-1] + f*cos(theta) into x[i]
put y[i-1] + f * sin(theta) into y[i]
end repeat
Any mistakes are mine - any correct bits are courtesy of Google -)
-- Alex.
On 03/12/2020 19:48, Roger Guay via use-livecode wrote:
Can someone please translate the code below into LC ? I believe it to be Python?
alpha=2
n=1000
x=rep(0,n)
y=rep(0,n)
for (i in 2:n){
theta=runif(1)*2*pi
f=runif(1)^(-1/alpha)
x[i]=x[i-1]+f*cos(theta)
y[i]=y[i-1]+f*sin(theta)
}
Thanks very much,
Roger
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