The center (loc) of the rect is the center of the triangle. So to get a triangle of width W, you need to set the height and width of the grc to 2*W/sqrt(3).
Thanks, Brian On Dec 27, 2019, 10:31 AM -0500, Sannyasin Brahmanathaswami via use-livecode <use-livecode@lists.runrev.com>, wrote: > Regular Polygon Tool: > > If you create a triangle grc and set its width and height to 243pt > > the tool positions the top of the triangle to center of the top line of the > rect and leaves margins on the left and right sides. Thus, the triangle > itself doesn't take the width of 243pt. It like ist has margins left and > right… > > how to does have precise control over the size of the triangle (not the rect)? > > right now I have to build a "measuring grc/ruler" underneath, set it width to > 243, and fiddle with the triangle until it matches my "ruler" > > BR > > > _______________________________________________ > use-livecode mailing list > use-livecode@lists.runrev.com > Please visit this url to subscribe, unsubscribe and manage your subscription > preferences: > http://lists.runrev.com/mailman/listinfo/use-livecode _______________________________________________ use-livecode mailing list use-livecode@lists.runrev.com Please visit this url to subscribe, unsubscribe and manage your subscription preferences: http://lists.runrev.com/mailman/listinfo/use-livecode
