Hi Marco,
thanks for taking the time to report this issue.
This behavior - annoying as it may be - is however entirely expected.
Quoting from the bash manpage:
" Pipelines
A pipeline is a sequence of one or more commands separated by the char‐
acter |. The format for a pipeline is:
[time [-p]] [ ! ] command [ | command2 ... ]
[...]
If the time reserved word precedes a pipeline, the elapsed as well as
user and system time consumed by its execution are reported when the
pipeline terminates. The -p option changes the output format to that
specified by POSIX. The TIMEFORMAT variable may be set to a format
string that specifies how the timing information should be displayed;
see the description of TIMEFORMAT under Shell Variables below."
So bash has an internal version of "time" and it only accepts -p as a
parameter.
/usr/bin/time is a separate program, and, as you noticed, it works
correctly if you make sure *it* is called and not bash's version.
If you specifically want to change the output format, the bash variable
TIMEFORMAT may be of use to you. See also question G4 of the bash FAQ
here: http://tiswww.case.edu/php/chet/bash/FAQ
As for documenting this in the manpage, it already is. Quoting from time(1):
"Users of the bash shell need to use an explicit path in order to run the
external time command and not the shell builtin variant. On system where time
is installed in /usr/bin, the first example would become /usr/bin/time wc
/etc/hosts"
I hope this clears everyhting up :)
** Changed in: bash (Ubuntu)
Status: New => Invalid
** Changed in: time (Ubuntu)
Status: New => Invalid
--
time: Time does not parse its parameters
https://bugs.launchpad.net/bugs/238061
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